(4x*(4x+1))/2+4*(3x+1)=(3x+2)^2

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Solution for (4x*(4x+1))/2+4*(3x+1)=(3x+2)^2 equation:


x in (-oo:+oo)

(4*x*(4*x+1))/2+4*(3*x+1) = (3*x+2)^2 // - (3*x+2)^2

(4*x*(4*x+1))/2+4*(3*x+1)-(3*x+2)^2 = 0

(4*x*(4*x+1))/2+4*(3*x+1)-1*(3*x+2)^2 = 0

(4*x*(4*x+1))/2+(2*4*(3*x+1))/2+(-1*2*(3*x+2)^2)/2 = 0

4*x*(4*x+1)+2*4*(3*x+1)-1*2*(3*x+2)^2 = 0

16*x^2-18*x^2+28*x-24*x-8+8 = 0

4*x-2*x^2 = 0

4*x-2*x^2 = 0

2*x*(2-x) = 0

2-x = 0 // - 2

-x = -2 // * -1

x = 2

2*x*(x-2) = 0

(2*x*(x-2))/2 = 0

(2*x*(x-2))/2 = 0 // * 2

2*x*(x-2) = 0

( 2*x )

2*x = 0 // : 2

x = 0

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 0, 2 }

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